Adott egy karakterláncot meg kell vizsgálnunk, hogy lehet-e ebből a karakterláncból palindromot tenni, miután pontosan egy karaktert eltávolítunk belőle.
Példák:
Input : str = abcba Output : Yes we can remove character ‘c’ to make string palindrome Input : str = abcbea Output : Yes we can remove character ‘e’ to make string palindrome Input : str = abecbea It is not possible to make this string palindrome just by removing one character
Ezt a problémát úgy tudjuk megoldani, hogy megtaláljuk az eltérés helyzetét. A karakterlánc hurkolását úgy kezdjük, hogy mindkét végén tartunk két mutatót, amelyek a középső pozíció felé haladnak minden iteráció után ez az iteráció leáll, ha eltérést találunk, mivel csak egy karaktert lehet eltávolítani, itt két választásunk van
Eltérés esetén távolítsa el a bal mutatóval mutató karaktert, vagy távolítsa el a jobb egérmutatóval mutató karaktert.
Mindkét esetet ellenőrizni fogjuk, hogy ne felejtsük el, mivel mindkét oldalról azonos számú lépést tettünk meg, ennek a középső karakterláncnak is palindromnak kell lennie egy karakter eltávolítása után, így ellenőrizzük a két részstringet az egyik a bal, a másik a jobb karakter eltávolításával, és ha az egyik palindrom, akkor teljes string palindromot készíthetünk a megfelelő karakter eltávolításával, és ha nem lehetséges, akkor mindkét részkarakterlánc nem teljes. palindrom adott kényszer alatt.
Végrehajtás:
C++// C/C++ program to check whether it is possible to make // string palindrome by removing one character #include
// Java program to check whether // it is possible to make string // palindrome by removing one character import java.util.*; class GFG { // Utility method to check if // substring from low to high is // palindrome or not. static boolean isPalindrome(String str int low int high) { while (low < high) { if (str.charAt(low) != str.charAt(high)) return false; low++; high--; } return true; } // This method returns -1 if it is // not possible to make string a palindrome. // It returns -2 if string is already // a palindrome. Otherwise it returns // index of character whose removal can // make the whole string palindrome. static int possiblePalinByRemovingOneChar(String str) { // Initialize low and right // by both the ends of the string int low = 0 high = str.length() - 1; // loop until low and // high cross each other while (low < high) { // If both characters are equal then // move both pointer towards end if (str.charAt(low) == str.charAt(high)) { low++; high--; } else { /* * If removing str[low] makes the * whole string palindrome. We basically * check if substring str[low+1..high] * is palindrome or not. */ if (isPalindrome(str low + 1 high)) return low; /* * If removing str[high] makes the whole string * palindrome. We basically check if substring * str[low+1..high] is palindrome or not. */ if (isPalindrome(str low high - 1)) return high; return -1; } } // We reach here when complete string // will be palindrome if complete string // is palindrome then return mid character return -2; } // Driver Code public static void main(String[] args) { String str = 'abecbea'; int idx = possiblePalinByRemovingOneChar(str); if (idx == -1) System.out.println('Not Possible'); else if (idx == -2) System.out.println('Possible without ' + 'removing any character'); else System.out.println('Possible by removing' + ' character at index ' + idx); } } // This code is contributed by // sanjeev2552
# Python program to check whether it is possible to make # string palindrome by removing one character # Utility method to check if substring from # low to high is palindrome or not. def isPalindrome(string: str low: int high: int) -> bool: while low < high: if string[low] != string[high]: return False low += 1 high -= 1 return True # This method returns -1 if it # is not possible to make string # a palindrome. It returns -2 if # string is already a palindrome. # Otherwise it returns index of # character whose removal can # make the whole string palindrome. def possiblepalinByRemovingOneChar(string: str) -> int: # Initialize low and right by # both the ends of the string low = 0 high = len(string) - 1 # loop until low and high cross each other while low < high: # If both characters are equal then # move both pointer towards end if string[low] == string[high]: low += 1 high -= 1 else: # If removing str[low] makes the whole string palindrome. # We basically check if substring str[low+1..high] is # palindrome or not. if isPalindrome(string low + 1 high): return low # If removing str[high] makes the whole string palindrome # We basically check if substring str[low+1..high] is # palindrome or not if isPalindrome(string low high - 1): return high return -1 # We reach here when complete string will be palindrome # if complete string is palindrome then return mid character return -2 # Driver Code if __name__ == '__main__': string = 'abecbea' idx = possiblepalinByRemovingOneChar(string) if idx == -1: print('Not possible') else if idx == -2: print('Possible without removing any character') else: print('Possible by removing character at index' idx) # This code is contributed by # sanjeev2552
// C# program to check whether // it is possible to make string // palindrome by removing one character using System; class GFG { // Utility method to check if // substring from low to high is // palindrome or not. static bool isPalindrome(string str int low int high) { while (low < high) { if (str[low] != str[high]) return false; low++; high--; } return true; } // This method returns -1 if it is // not possible to make string a palindrome. // It returns -2 if string is already // a palindrome. Otherwise it returns // index of character whose removal can // make the whole string palindrome. static int possiblePalinByRemovingOneChar(string str) { // Initialize low and right // by both the ends of the string int low = 0 high = str.Length - 1; // loop until low and // high cross each other while (low < high) { // If both characters are equal then // move both pointer towards end if (str[low] == str[high]) { low++; high--; } else { /* * If removing str[low] makes the * whole string palindrome. We basically * check if substring str[low+1..high] * is palindrome or not. */ if (isPalindrome(str low + 1 high)) return low; /* * If removing str[high] makes the whole string * palindrome. We basically check if substring * str[low+1..high] is palindrome or not. */ if (isPalindrome(str low high - 1)) return high; return -1; } } // We reach here when complete string // will be palindrome if complete string // is palindrome then return mid character return -2; } // Driver Code public static void Main(String[] args) { string str = 'abecbea'; int idx = possiblePalinByRemovingOneChar(str); if (idx == -1) Console.Write('Not Possible'); else if (idx == -2) Console.Write('Possible without ' + 'removing any character'); else Console.Write('Possible by removing' + ' character at index ' + idx); } } // This code is contributed by shivanisinghss2110
<script> // JavaScript program to check whether // it is possible to make string // palindrome by removing one character // Utility method to check if // substring from low to high is // palindrome or not. function isPalindrome(str low high) { while (low < high) { if (str.charAt(low) != str.charAt(high)) return false; low++; high--; } return true; } // This method returns -1 if it is // not possible to make string a palindrome. // It returns -2 if string is already // a palindrome. Otherwise it returns // index of character whose removal can // make the whole string palindrome. function possiblePalinByRemovingOneChar(str) { // Initialize low and right // by both the ends of the string var low = 0 high = str.length - 1; // loop until low and // high cross each other while (low < high) { // If both characters are equal then // move both pointer towards end if (str.charAt(low) == str.charAt(high)) { low++; high--; } else { /* * If removing str[low] makes the * whole string palindrome. We basically * check if substring str[low+1..high] * is palindrome or not. */ if (isPalindrome(str low + 1 high)) return low; /* * If removing str[high] makes the whole string * palindrome. We basically check if substring * str[low+1..high] is palindrome or not. */ if (isPalindrome(str low high - 1)) return high; return -1; } } // We reach here when complete string // will be palindrome if complete string // is palindrome then return mid character return -2; } // Driver Code var str = 'abecbea'; var idx = possiblePalinByRemovingOneChar(str); if (idx == -1) document.write('Not Possible'); else if (idx == -2) document.write('Possible without ' + 'removing any character'); else document.write('Possible by removing' + ' character at index ' + idx); // this code is contributed by shivanisinghss2110 </script>
Kimenet
Not Possible
Időbonyolultság: O(N)
A tér összetettsége: O(1)
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